Question

The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Answer 1

Distance covered = x km

Total fair = y Rs

As according to the question for the first kilometre, the fares is Rs 8

For remaining distance 5 rs per km

So, after removing 1 km for which the charge is Rs 8,we left with (x-1) km

Total charge:

$y = 8 + 5(x - 1) \\ \\ y = 8 + 5x - 5 \\ \\ y = 5x + 3$
This linear equation can be expressed in standard form
$y - 5x = 3 \\ \\ or \\ \\ - 5x + y = 3 \\ \\ or \\ - 5x + y - 3 = 0 \\ \\ or \\ \\ 5x - y + 3 = 0$
For making graph put value of x and find the value of y.

Hope it helps you.

Answer 2

Step-by-step explanation:

click on picture you will

see your full answer.

This is correct answer.

I hope it's help you!!

please mark me as brainliest answer.