Question

The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Answer 1

Fare for first 1km=rupees 8

Fare for subsequent km = rupees 5

distance covered =x km

total fare =rupees y

according to the question

1×8+5(x-1)=y

8+5x-5=y

5x+3=y

y=5x+3

•for x=0

y=5×0+3

=0+3

=3

(0,3)

•for x=1

y=5×1+3

=5+3

=8

(1,8)

•for x=-1

y=5×-1+3

=-5+3

=-2

(-1,-2)

by using this coordinates (0,3),(1,8)and(-1,-2)...

you can draw the graph ...

i hope that this answer would be useful for you...

and mark me as a brainliest answer..

please yrr...

Answer 2

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

x 0  1 2

y 3 8  13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3    ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)