Question

The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 15 and Rs 8 for every subsequent kilometer. a) Write the linear equation representing the above information. b) Draw the graph. c) Find the fare for 12 km. d) If Manoj paid for Rs 159 , find how far did he travel.

Answer 1

Answer:

Step-by-step explanation:

15+8x

c)15+12(8)=111

d)15+8x=159

8x=144

x=18

Answer 2

The linear equation representing the above information is y= 8x+7

The fare for 12 km is Rs. 103

Manoj travels the distance of 19 km.

Step-by-step explanation:

(a) let total distance = x km

total fare= y

fare for the first km= Rs.15

remaining distance = (x-1)

fare for the remaining distance = 8(x-1)

total fare (y) = 15+ 8(x-1)

y= 15+8x-8

y= 8x+7

The linear equation representing the above information is y= 8x+7

(b) the graph of this linear equation is shown below with the cordinates

(0,7) , (1,15) , (2,23)

(c) fare for 12 km

y= 15+8(12-1)

y= 15+ 8(11)

y= 15+ 88

y= Rs. 103

hence , the fare for 12 km is Rs. 103

(d)

if manoj paid Rs. 159

y= 15+ 8(x-1)

159 = 15+ 8x-8

159 = 8x+7

159-7= 8x

152=8x

$x= \frac{152}{8}$

x= 19 km

hence, manoj travels the distance of 19 km.

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