The taxi fare in a city is as follows: For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. [Taking the distance covered as x km and total fare as Rs y, Tick from the following options its linear equation and some possible solutions.
x=5y+3, solutions=(8,1), (53,10), (13,2), (-7,-2)
y=3x+5 solutions= (1,8), (2,11), (3,14) (10,35)
y=5x+3 solutions= (1,8), (2,13), (3,18) (10,53)
None of these
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Answers
Answered by
2
Answer:
option c
Step-by-step explanation:
total fare = y
total distance = X
distance travelled after 1 km = (x-1) km
y = 8 + 5 ( x-1)
y = 8 + 5x -5
y = 5x + 3
Answered by
0
Answer:
y = 5x + 3
Step by step explanation:
Total distance covered = x km
Total fare for the journey = y km
Fare for the first km = Rs. 8
Fare for the remaining distance = Rs. 5 (x -1)
=> Rs. (5x - 5)
∴ Total fare for the journey= Fare for the 1st km + Fare for the remaining distance
=> y = 8 + 5x -5
=> y = 5x + 3
=>The solutions are (1,8) , (2,13) , (3, 14) , (10,35)
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