The taxi fare in a city is as follows: For the first kilometre, the fare is RS.8
and for the subsequent distance it is Rs.5 per km. Taking the distance
covered as x km and total fare as Rs. y , write a linear equation for this
information
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Taxi fare for first kilometer = Rs. 8
Taxi fare for subsequent distance = Rs. 5
Total distance covered =x
Total fare =y
Since the fare for first kilometer = Rs.8
According to problem,
Fare for (x–1) kilometer = 5(x−1)
So, the total fare y=5(x−1)+8
⇒y=5(x−1)+8
⇒y=5x–5+8
⇒y=5x+3
Hence, y=5x+3 is the required linear equation.
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