The taxi fare in a city is as follows: For the first kilometer, the fare is ₹ 9 and for the subsequent distance it is ₹6 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information. Show all the steps written in proper order.
Answers
Answer:
Step-by-step explanation:
Given,Total distance covered= x km=1+(x-1)km
Fare For first kilometre= ₹8
Fare for subsequent distance= ₹5 per km
Fare for next(x-1)km= 5(x-1)
A.T.Q
Total fare= y
8+5(x-1)=y
8+5x-5=y
5x-y+3=0
Which is the required linear equation.
It can also be written as y= 5x+3
When X = 0 ,then Y = 3,When x=1, then y= 5+3=8
When x= 2, then y= 10+3=13
[Table & graph are on the attachment]
Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.
========================================================
Hope this will help you.....
Given,
Total distance covered= x km=1+(x-1)km
Fare For first kilometre= ₹9
Fare for subsequent distance= ₹6 per km
Fare for next(x-1)km= 6(x-1)
A.T.Q
Total fare= y
9+6(x-1)=y
9+6x-6=y
15x-y-6=0
Which is the required linear equation.
It can also be written as y= 15x-6
When X = 3/2 ,then Y = 7,When x=1, then y= 5+3=8
When x= 2, then y= 10+3=13
[Table & graph are on the attachment]
Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.
========================================================