Question

the taxi fare in a city is as follows for the first kilometers the taxi is Rs8 and for the subsequent distance it is Rs5 per km write a linear equation for this and it's graph

Answer 1

let the initial on kilometre be x and the next extra kilometres be y.
therefore the equation will be x+5y where x will be constant as 8
and the graph will be the line joining the points
1) (8,5)
2) (8,10)

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)