The taxi fare in a city is as follows: for the first kilometre, the fare is Rs 18 and for the subsequent distance it is Rs 10 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information. And draw the graph and find the fare for 21 km.
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Answer:
let the total distance covered be x and the total fare be y.
cost for first km=18
remaining km=(x-1)km
cost for remaining km=10(x-1)
=10x-10
ATQ
y=18+10x-10
=y=8+10x
=8+10x-y=0
=10x-y+8=0 is the linear equation
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