Question

The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for

the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and

total fare as Rs y, write a linear equation for this information, and draw its graph.​

Answer 1

Answer:

see the answer here....

Answer 2

Given :-

A taxi fare in a city charges Rs. 8 for 1st kilometre and for subsequent km it charges Rs. 5 per kilometre .

Need to find: Linear equation and draw a graph .

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━⠀⠀⠀

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❍ DIAGRAM:-

$\bf\blue{In~the~above~attachment.}$

Solution :-

$\longmapsto\tt{Let\:the\:distance\:covered\:be=x\:km}$

$\longmapsto\tt{Fare\:for\:travelling=Rs.y}$

$\longmapsto\tt{Fare\:for\:1st\:km=Rs.8}$

$\longmapsto\tt{For\:Subsequent\:km=Rs.5}$

A.T.Q :

$\longmapsto\tt{y=8\times{1}+(x-1)\times{(-5)}}$

$\longmapsto\tt{y=8+5x-5}$

$\longmapsto\tt{y=8-5+5x}$

$\longmapsto\tt\bf{y=5x+3}$

So , The Linear Equation is y = 5x+3 ..

Now ,

$\begin{tabular}{|c|c|c|c|c|}\cline{1-5}\sf x & \sf 0 & \sf 1 & \sf 2 & \sf 3\\\cline{1-5}\sf y & \sf 3 &\sf 8&\sf 13&\sf 18\\\cline{1-5}\end{tabular}$

Refer to the Attachment !

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