Question

The taxi fare in a city is as follows: For the first kilometer, the fare is Rs.8 and for the subsequent distance it is Rs. 5 per km. Taking the distance covered as x km. and total fare as Rs.y, write a linear equation for this information and draw its graph​

Answer 1

Answer:

Given,Total distance covered= x km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

 

Fare for next(x-1)km= 5(x-1)

 

A.T.Q

 

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

 

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When

When X=1, then y= 5+3=8

Now plot the points A(0,3), B(1,8) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.

========================================================

Hope this will help you.....

Answer 2

$\\ \sf\large\red{\underline{ given : }}$

8Rs is charged for 1st km.

5Rs is charged for each next km.

Total distance covered is "x".

Total fare is "y".

$\sf\large\red{\underline{to \: find : }}$

Equation and graph of this total fare.

$\\ \sf\large\red{\underline{ solution : }}$

Total distance = x

➽8Rs is charged for 1st km.

So, rest distance remained = (x - 1)km

➽Cost of fare for (x-1)km = 5( x - 1 )Rs

Total cost = y

y = Cost for 1st km + cost of (x - 1)km

y = 8 + 5(x-1)

y = 8 + 5x - 5

y = 3 + 5x

The required equation is

➜ y = 3 + 5x