The taxi fare in a city is as follows :for the first kilometre the fare is Rs 10 and for the subsequent distance it is Rs 6 per km taking the distance covered as x km and total fare as Rs y, write a linear equations for this information
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Total distance covered = x km
Fare for 1st km = Rs 10
Fare for subsequent of the distance = Rs6 subsequent distance = Rs 6(x-1)
Therefore, Total fare = Fare for 1st km+ Fare for the subsequent(x-1)km
=> y= 10+6(x-1)
y= 10+6x-6
=> y= 6x+4
hope this helps you
Fare for 1st km = Rs 10
Fare for subsequent of the distance = Rs6 subsequent distance = Rs 6(x-1)
Therefore, Total fare = Fare for 1st km+ Fare for the subsequent(x-1)km
=> y= 10+6(x-1)
y= 10+6x-6
=> y= 6x+4
hope this helps you
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