the taxi fare in a city is as follows for the first kilometer, the fare is Rs 8 and for the subsequent distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw this graph
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Answered by
10
Here is the complete explanation to the mentioned question.
Fare for the first km = Rs 8
Total distance covered = x km
After travelling first km, remaining distance = (x – 1) km
Rate of fare = Rs 5 per km
Fare for (x – 1) km = 5 × (x –1)
Total fare = Rs y
Fare for the first km + fare for the remaining distance = y
8 + (x – 1) 5 = y
8 + 5x – 5 = y
5x – y + 3 = 0
Fare for the first km = Rs 8
Total distance covered = x km
After travelling first km, remaining distance = (x – 1) km
Rate of fare = Rs 5 per km
Fare for (x – 1) km = 5 × (x –1)
Total fare = Rs y
Fare for the first km + fare for the remaining distance = y
8 + (x – 1) 5 = y
8 + 5x – 5 = y
5x – y + 3 = 0
kruchi71:
thanks
Answered by
1
⇒ Let the total fare be = y Rs
⇒ Distance covered be = x km
⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)
⇒ y = 8 + 5 (x - 1)
⇒ y = 8 + 5x - 5
⇒ y = 5x + 3
⇒ The coordinates of the following linear equation
1) x = 0, y = 3 (0,3)
2) x = 1, y = 8 (1,8)
3) x = 2, y = 13 (2,13)
4) x = 3, y = 18 (3,18)
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