Question

The taxi fare in a city is as follows: For the first kilometre, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs.y, write a linear equation for this information and draw its graph.

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Answer 1

Step-by-step explanation:

If the distance covered us x then,

for first kilometer fare is 8 rupees and for subsequent kilometers it is 5 rupees so subtract 1 from x and add 8 in it, it will give you total value of expenditure that is y.

here like this:-

8+5(x-1)=y

5x+3=y

Answer 2

Answer:

5x - y + 3 = 0

Step-by-step explanation:

Let the total distance covered be

= x

Let the total fare be = y

We know, The fare first km is rupees 8 and for the for the subsequent distance it is rupees 5 so,

According to the Question

• 8 + 5(x - 1) = y
• 8 + 5x - 5 = y
• 5x + 3 = y
• Writing it in standard form,
• ax + by + c = 0

therefore, 5x - y + 3 = 0