Question

The taxi fare in a city is as follows : For the first kilometre ,the fare is ₹8 and for the first subsequent distance it is ₹5 per km. Taking the distance covered as X km and total fare as ₹ y, write a linear equation for this information .
On the basis above answer the following questions
1)Linear equation for the following situation
a) y=2x+5 b) y=5x+3 c) y=2x+8 d) y=5x+5
2)if y=11, then value of x
a) 3 b) 7 c)y=8. d) y=10
3)If value of x=3 then you will be
a) y=16 b) y=20 c) y=18 d) y=15
4)If fare of first km is ₹ 10 find equation
a) y=2x+5 b) y=5x+3 c) y=2x+8
d) y=5x+5
5)The number of solutions equation part (1)
a)unique b) two c) three d) infinite solution ​

Answer 1

Answer:

x 0 1 2

y 3 8 13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)

Step-by-step explanation:

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