The taxi fare in a city is as follows: For the first kilometer, the fare is Rs. 20 an for the subsequent distance it is Rs. 6 per km. Taking x km as the distance covered and Rs. y as the total fare, write a linean equation for this information and draw its graph.
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Given: The distance covered as x km and total fare is Rs. y.
Total fare =the fare for first km + the fare of the remaining distance
\therefore y=8+5\times (x-1)
\Rightarrow y=8+5x-5
\Rightarrow y=3+5x
For graph,
Putting x=0, we have y=3+5(0)=3
Putting x=1, we have y=3+5(1)=8
Putting x=2, we have y=3+5(2)=13
Hence,(0,3),(1,8) and (2,13) are solutions of equation.
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