the taxi fare in a city is as follows for the first kilometre the fare is rupees 10 and for the subsequent distance it is rupees 8 per km taking the distance covered as× km and total fare is rupees y write a liner equation for this information and its graph
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Answer:
Total fare = y
Total distance covered = x
Fair for the subsequent distance after 1st kilometre = Rs 5
Fair for 1st kilometre = Rs 8
A/q
y = 8 + 5(x-1)
⇒ y = 8 + 5x - 5
⇒ y = 5x + 3
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