Question

the taxi fare in a city is as follows.for the first kilometer, the fare is Rs.8, for the subsequent distance it is Rs. 5 per KM. taking the distance covered as x KM and total fare as Rs.y, write a linear equation for this information, and draw its graph.

Answer 1

Fare for 1st km= Rs 8
total distance= x km
After 1 Km remaining distance= x- 1 km
Rate of fare= Rs 5 per km
so, for (x-1)km = 5 x (x-1) 

Total = y = 8 + (x-1)5
8 + 5x - 5 = y
5x - y + 3= 0

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)