The taxi fare in a city is as follows: For the first kilometer, the fare is Rs. 8 and forthe subsequent distance it is Rs. 5 per km. Taking the distance covered as x kmand total fare as Rs. y, writes a linear equation for this information
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Answered by
6
y=8(x-1)+5
y=8x-8+5
y=8x+3
8x-y+3
y=8x-8+5
y=8x+3
8x-y+3
Answered by
1
y=8(x-1)+5
y=8x-8+5
y=8x+3
8x-y+3
y=8x-8+5
y=8x+3
8x-y+3
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