Question

The taxi fare in a city is as follows. For the first km, the fare is ₹ 10 and for subsequent distance it is ₹ 6 per km. Taking the distance covered as ‘x’ km and total fare as ₹ ‘y’, write a linear equation in two variables for the situation and find any two solutions.

Answer 1

Answer:

(0,4)/(1,10)

Step-by-step explanation:

Let distance = x

Total fare = y

subsequent distance= ruppes 5 per distance (x-1)

total force = 10×1+6(x-1)

y=10+6x-6

y=4+6x

first equation

y=4+6x

x=o

y=4+6×0

=4+0

y= 4

(0,4)

second equation

x=1

y=4+6×1

y=4+6

y=10

(1,10)