The taxi fare in a city is as follows For the first km , the fare is 10 and for the subspent distance it is 8per km Taking the distance caused as x km and total face as y Draw the graph vof above information
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Given :-
- Total distance covered= x km=1+(x-1)km
- Fare For first kilometre= ₹8
- Fare for subsequent distance= ₹5 per km
=> Fare for next(x-1)km= 5(x-1)
Total fare= y
8+5(x-1)=y
8+5x-5=y
=> 5x-y+3=0
When X = 0 ,then Y = 3,When x=1, then y= 5+3=8
When x= 2, then y= 10+3=13
REFER TO THE ATTACHMENT FOR GRAPH
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Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.
Attachments:
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