Question

The taxi fare in a city is as follows.
for the first two km, the fare is Rs.20 and for the subsequent distance it is Rs. 8 km. taking the distance covered as x km and total fare is Rs y .write a linear equation in two variables and draw it's graph​

Answer 1

Answer:

given

for the first 2 km the cost is 20

for other that is x-2 distance cost is 8(x-2)

=8x-16

also 20+(8x-16) =y

20+8x-16=y

8x+4=y _______(i)

placing the value of x

x=1

8(1) +4=y

8+4=y

12=y

at x=2

8(2) +4=y

16+4=y

20=y

therefore from this values we can make the graph