Question

The taxi fare in a city is charged as per the rates below. Rate for the first km of journey is Rs. 6 and rate for the subsequent distance covered is Rs 5 per km. Taking distance covered as x km and the total fare as Rs. y,Find the linear equation to represent this situation.

Answer 1

Answer :-

• We how to find the linear equation to represent the situation of taxi fare into the city according to its rates

Rate for First km = Rs.6

Rate of subsequent Distance = Rs.5 per km

A.T.Q

• It is already given in the question that the Total distance covered is x km and total fare is Rs. y

So, the linear equation will be

6 + 5x = xy

5x - xy + 6 = 0

(5-y)x + 6 = 0

That is the linear equation used to represent this situation

Answer 2

Answer:

Step-by-step explanation:

Let the distance covered = 'x ' km

Let the total fare = Rs y

Now, Rate for first 1 km = Rs 6

So, rate for subsequent distance travelled

=Rs 5 (x -1)

A/Q

y = 5(x -1) + 6

or, y = 5x - 5 + 6

or, y = 5x + 1 which is the required linear equation

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