Question

The taxi fare in a city is charged as per the rates stated below: Rate for the first kilometre of journey is Rs.5 and the rate for the subsequent distance covered is Rs 4 per km. Taking distance covered as x km and total fare as Rs y, the linear equation in two variables is framed as​

Answer 1

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• Rate for first kilometre = Rs 5

• The rate for the subsequent distance covered is Rs 4 per km.

• Total fare = Rs y

• Total distance covered = x km

• Fare for 1st km = Rs 5

• Subsequent distance = 4/km

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• Linear equation =?

Formula to be used :-

• Total fare = fare for 1st km + fare for rest distance.

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

Let the distance covered be x km.

Then,

Fare for rest distance will be = 4(x - 1)

A.T.Q :-

⟼ y = 5 + 4(x-1)

⟼ y = 5 + 4x - 4

⟼ y = 4x + 1

Hence ,the Linear equation formed is y = 4x + 1