Question

the taxi fare in a city is charged Rs 10 for the first km and @Rs 4 per km for subsequent distance covered. Write the linear equation to express the above statement

Answer 1

First km=10rs
Subsequent distance=rs4
Total distance=x
Total fare=y
Fare for (x-1) distance=4(x-1)
Total fare=4(x-1)+10
=4x-4+10
Y=4x-6

Then y=10+4x

Answer 2

let the total distance be x km and total cost be y

Now,10 rupees for first km and 4 rupees for rest

so,

y=1(10)+4(x-1)

Therefore, y=4x+6

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