Question

The taxi fare in a city is. Rs 15 for the first kilometre and Rs 8 for each subsequent kilometre . Taking the distance covers as x km and dare as Rs y write a linear equation

Answer 1

Here is the complete explanation to the mentioned question.

 

Fare for the first km = Rs 8

Total distance covered = x km

 

After travelling first km, remaining distance = (x – 1) km

Rate of fare = Rs 5 per km

Fare for (x – 1) km = 5 × (x –1)

Total fare = Rs y

Fare for the first km + fare for the remaining distance = y

8 + (x – 1) 5 = y

8 + 5x – 5 = y

5x – y + 3 = 0

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)

REFER THE ATTACHMENT FOR GRAPH