THE TAXI FARE IN CITY IS AS FOLLOWS FOR THE FIRST KM THE FARE IS RS 5 AND FOR THE SUBSEQUENT DISTANCE IT IS RS 10 PER KM TAKING THE DISTANCE COVERED AS X KM AND TOTAL FARE AS RS Y WRITE A LINERA EQUATION FOR TS INFORMATION ANDDRAWITS GRAPH
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let the total distance covered be x and fare be y.
Fare for the first km is = RS 5
Subsequent km / remaining km = x-1[ total km - 1st km ]
fare for subsequent km = 10 [ x-1]
so total fare
y = 5 + 10+[x-1]
y = 5 + 10x -10
y = 10x - 5
Hope this will help u if yes then hit that thanx button below!!:D:)
Fare for the first km is = RS 5
Subsequent km / remaining km = x-1[ total km - 1st km ]
fare for subsequent km = 10 [ x-1]
so total fare
y = 5 + 10+[x-1]
y = 5 + 10x -10
y = 10x - 5
Hope this will help u if yes then hit that thanx button below!!:D:)
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