The taxi fare in city is such that Rs50 is the fixed amount and Rs16 per km is charged .Taking distance x km and totaj fare as Rs.y . Write linear equation in x y .What is the total fare for 20km also draw the graph in given equation
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We have to find y.
Now, y = 50 + (x - 2) 16
y = 50 + (20-2) 16
y = 50 + 18 × 16
y = 288.
Hence, Rs. 288
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