The taxi in a city is as follows : for the first kilometre the fare is rs 8 and for the subsequent distance it is rs 5 per km. Taking the distance covered as x km and total fair as rs y write a linear equation for this information and draw its graph. Linear equation in two variable...
Answers
Step-by-step explanation:
Taxi fare for first kilometer = Rs. 8
Taxi fare for subsequent distance = Rs. 5
Total distance covered =x
Total fare =y
Since the fare for first kilometer = Rs.8
According to problem,
Fare for (x–1) kilometer = 5(x−1)
So, the total fare y=5(x−1)+8
⇒y=5(x−1)+8
⇒y=5x–5+8
⇒y=5x+3
Hence, y=5x+3 is the required linear equation.
Now the equation is
y=5x+3 ...(1)
Now, putting the value x=0 in (1)
y=5×0+3
y=0+3=3 So the solution is (0,3)
Putting the value x=1 in (1)
y=5×1+3
y=5+3=8. So the solution is (1,8)
Putting the value x=2 in (1)
y=5×2+3
y=10+3=13. So the solution is (2,13)
solution
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Answer:
y = 8 + 5*(x-1)
Step-by-step explanation:
When you move for 1 km, the fare will be Rs. 8
When you move for 2 kms, the fare will be Rs. 13
The fare will be variable only for going more than 1 km.