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Answer:
Given:
The two zeros of a quadratic polynomial are -4 and -6.
To find:
The sum and product of zeros.
The value of coefficient b.
Solution:
1) The relation between the coefficient and zeroes of the quadratic equation is given by:
ax²+bx+c = 0
Let p and q are the zeroes of the given quadratic equation then:
Sum of zeroes is = p+q = -b/a
Product of zeroes is = pq = c/a
2) So according to the question
Sum of zeroes is
-4+(-6)
-10 = -b/a
10 = b/a-------(I)
Product of zeroes is
-4.-6
24 = c/a----------(II)
From the equations (I) and (II)
a = 1
b = 10
c = 24
The sum and product of zeros are -10 and 24 repectively.
The value of coefficient b is 10.
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