English, asked by gourisaxena261, 1 day ago

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Answers

Answered by ErrorGurI
0

Answer:

Given:

The two zeros of a quadratic polynomial are -4 and -6.

To find:

The sum and product of zeros.

The value of coefficient b.

Solution:

1) The relation between the coefficient and zeroes of the quadratic equation is given by:

ax²+bx+c = 0

Let p and q are the zeroes of the given quadratic equation then:

Sum of zeroes is = p+q = -b/a

Product of zeroes is = pq = c/a

2) So according to the question

Sum of zeroes is

-4+(-6)

-10 = -b/a

10 = b/a-------(I)

Product of zeroes is

-4.-6

24 = c/a----------(II)

From the equations (I) and (II)

a = 1

b = 10

c = 24

The sum and product of zeros are -10 and 24 repectively.

The value of coefficient b is 10.

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