Question

The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks + 7 the highest code is 97 what is the lowest marks

Answer 1

Let the lowest score be x

Given, the student in the class has obtained twice the lowest marks + 7 = 2x + 7

Given, the highest score is 97


According to the question,

2x + 7 = 97

➾ 2x = 97 - 7

➾ 2x = 90

➾ x = $\dfrac{90}{2}$

➾ x = 45



∴ The lowest marks in the class is 45



Let's check out the solution :-

2x + 7 = 97

By putting the value of x,

➾ 2 × 45 + 7 = 90

➾ 90 + 7 = 97

➾ 97 = 97

∴ LHS = RHS ✔✔



∴ The lowest score is 45


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Answer 2

$\bold {here \: is \: your \: answer}$
suppose the lowest marks be x
so highest =2x
then question in given +7 marks

then 2x+7=97
2x=97-7
2x=90
x=90/2
x=45

so lowest marks= 45


thanks for asking this question.....

****be brainly