the temperature at 12 moon was 10^c above zero. if it decreases at the the rate of 2^c hours until midnight at what time would temperature be 8^c below zero what would be the temperature at midnight
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Answer:
12 noon, the temperature =10°C above zero
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°C
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°C
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hours
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hours
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PM
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be =
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)=−14°C
12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)=−14°CSo, at 12 midnight the temperature will be−14°C.