Question

the temperature at noon was 10 °C above zero . if it decreases at the rate of 2°C per hour until midnight , at what time would be the temperature be 8°C below zero ? what would be the temperature at midnight​

Answer 1

At 12 noon, the temperature =10°C above zero

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°C

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°C

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hours

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C 

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hours

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PM

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = 

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)=−14°C

At 12 noon, the temperature =10°C above zeroThe temperature is decreasing at 2°C per hour8°C below zero =−8°CSo, total fall in temperature from 10°C to 0°C and from 0°C to −8°C=18°CSince the temperature falls 2°C in every one hour.Therefore, to decrease 18°C, time taken = 18/2= 9 hoursPresent time is 12 noon so, the time when the temperature is −8°C =12noon+9hoursSo, The time at which the temperature will be −8°C=9PMAt 9 PM, the temperature is −8°C, the temperature at 12 midnight will be = (−8°C)+(−2°C×3hours)=(−8°C)+(−6°C)=−14°CSo, at 12 midnight the temperature will be−14°C.