the temperature at which 500cc of a gas exert temperature to 93 Kelvin occupies half its original volume pressure constant
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P= CONSTANT.
V1=500
V2=250
T1=295OC
T2=?
APPLY CHARLE'S LAW
V1/T1=V2/T2
500/293=250/T2
146.5K=T2
V1=500
V2=250
T1=295OC
T2=?
APPLY CHARLE'S LAW
V1/T1=V2/T2
500/293=250/T2
146.5K=T2
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