Question

the temperature at which Methane molecule have the same average kinetic energy as that of oxygen molecule at 27 degree celsius is

Answer 1

Answer: At -23 °C, methane molecule will have the same kinetic energy as that of oxygen molecule.

Explanation: Methane is a polyatomic molecule and oxygen is a diatomic molecule.

Average kinetic energy for a polyatomic mole = 3kT

Average kinetic energy for a diatomic molecule = $\frac{5}{2}kT$

Temperature of oxygen molecule = 27 °C = (273 + 27) = 300K

We are given that the average kinetic energy of the two molecules are equal. Hence,

$\frac{5}{2}\times k(300K)=3kT$

T = 250K or

T = -23 °C

Answer 2

Explanation:

KE directly proportional to Absolute temperature

so KECH4/KEO2= TCH4/TO2

here KECH4=KEO2 so KECH4/KEO2=1 then

1=TCH4/27℃

therefore TCH4=27℃