Question

The temperature at which speed of sound in air becomes double of its value at 0 °C is .......... .
(a) 273 K
(b) 546 K
(c) 1092 K
(d) 0 K

Answer 1

Answer:

For getting double the speed of sound we need to increase the temperature four times which is 1092K.

Explanation:

Since, we know that speed of sound is $\sqrt {\gamma RT}$

Here, γ is ratio of specific heat for air it is assumed to be 1.4 , R is gas constant which is 287J/KGK and T is temperature in kelvin.

Since we know that

K=273+°C

For 0°C

K=273+0=273

The only variable in the formula of speed of sound is temperature, so for double the speed of sound we need to quadruple the temperature.

Speed of sound, a = $\sqrt{\gamma RT}$

For 273 K

a=$\sqrt{1.4 \times 287 \times273}$

=331.19 m/s

For getting double the speed of sound we need to quadruple the temperature.

That is 273 x 4=1092 K.

For 1092 K the speed of sound is = 663.60 m/s

Hence, the correct option is (c). 1092 K.

Answer 2

Answer:

,

Explanation:

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