Question

The temperature at which speed of sound in air becomes
double of its value at 27° C is
(a) 54°C (b) 327°C
(c) 927°C (d) None of these

Answer 1

Answer:

Explanation:

ANSWER

Speed of sound in air is given as

M

0

​

3RT

​

​

Thus the speed V∝

T

​

Thus is velocity becomes double, the temperature must go to four times its initial value.

Initial temperature=27+273=300K

Hence final temparature=1200K=927

∘

C

Answer 2

Explanation:

(c)927 degree C is correct

(c)927 degree C is correct plz mark me as brainliest