Question

The temperature changes from 27 to 327 find the ratio of kinetic energy of molecules at two temperature

Answer 1

In the question, the unit of the temperature is not given. Rewriting it with the necessary changes.

Question: The temperature changes from 27K to 327K. Find the ratio of kinetic energy of molecules at two temperatures.

Ans:

• The kinetic energy of molecules is given by                                                                                 E = 1.5kT,

where k is the Boltzmann's constant                                                                                                                     and T is the temperature.    

• Now, in SI units,

        T₁ = 27+273 = 300 K

        and    T₂ = 327+273 = 600 K

• So, ratio of kinetic energies is

        E₁/E₂ = 1.5kT₁ / 1.5kT₂ = 300/600 = 1/2

Answer 2

The ratio of kinetic energies is 1:2 or 1/2.

Step-by-step explanation:

The kinetic energy of molecules is given by                                                       E = 1.5 k.T

Where k is the Boltzmann's constant and T is the temperature.    

Now, in SI units:

Convert the temperature in Kelvin (K).

T₁ = 27 + 273 = 300 K

T₂ = 327 + 273 = 600 K

The ratio of kinetic energies is

E₁/E₂ = 1.5 kT₁ / 1.5 kT₂ = 300/600 = 1/2

Thus the ratio of kinetic energies is 1:2 or 1/2.

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