The temperature co- efficient of resistance of a wire is 0.00125 °C^-1. At 300°C its resistance 1 ohm.The resistance of the wire will be 2 ohm at
1) 1100 k
2) 1673 K
3) 1154 K
4) 1400 K
Answers
Answered by
15
Q]_____
Use R = R0 = ( 1 + αT ) because variation of resistance is exceeding 6%
R1 = R0 ( 1 + αt1 )
∴ 1 = R0 [ 1 + 0.00125 × 300 ] _[i]
R2 = R0 ( 1 + αt2 )
∴ 2 = R0 [ 1 + αt2 ]
2 = R0 [ 1 + 0.00125 × t2 ] _[ii]
Divide eq. [ii] [i], we get
2 = 1 + 0.00125 t2 / 1 +0.00125× 300
or, t2 = 1400°C
t2 = 1673 K
Therefore Solution is 2nd option
Answered by
1
Answer:
option 2 is correct 1673k....
Hope it will be helpful ☺️ thank you!
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