Question

The temperature coefficient of resistance for a wire is 0.00125/oC. At 27°K its
resistance is 1 ohm. Find the temperature at which the resistance becomes 2 ohm.

(its 27k not C)

Answer 1

Answer:

Step 1: Applying Relation between Temperature and Resistance

R=R

0

(1+α(T

2

−T

1

))

Given Initial resistance at 300K is 1Ω.

Let temperature be T when final resistance becomes 2Ω

⇒ 2Ω=1Ω(1+0.00125(T−300K))

⇒ 1=

4

5

×10

−3

(T−300K)

∴ T=1100K

Hence correct Option is A

Explanation:

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