Question

The temperature gradient of a rod of length 1 m is 60°C/m.lf the temperature of hot and is 30°C the temperature at the other end is

Answer 1

Answer:

Correct option is

B

−10

o

C

Temperature gradient =

l

θ

1

−θ

2

Here, θ

1

=30

o

C;l=0.5m

∴80=

0.5

30−θ

2

θ

2

=30−80×0.5

⇒θ

2

=30−40=−10

o

C

Answer 2

It's another side temperature is 30 C