Physics, asked by hproshankh, 6 months ago

The temperature of 0.05 kg of air is raised
by 1°C at constant volume. Calculate the
increase in intermal energy (Cv = 718 J kg C)​

Answers

Answered by anki509dd
0

Explanation:

उप eiehegeuebejebsihe

Answered by akshay111367
1

Explanation:

heat = ΔQ=Mass × specific heat×temperature change=15×0.2×5 cal=15 cal

Also, isochoric process implies work done =0

Applying first law, Change in internal energy= ΔQ =15 cal

marks brainlist

Similar questions