The temperature of 100 g of water is to be raised from 10°C to 40°C by adding steam. then the
amount of steam required for this purpose is
1) 4.7 g
2) 7.4g
3) 6g
4) 5g
Answers
heat(q) required to raise temp of 100g water from is 10 to 40 is
q=mc∆t
q=(100)(4.2)(30)
q=12600J
now is q is given by steam
q=mL
12600=m(2260)
m=5.57
approx 5 or 6. error might be in latent heat value pls follow these steps by putting exact value
hope it helps u
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Concept:
The amount of heat needed to raise a substance's temperature by one degree Celsius in one gram is also known as specific heat.
It is formulated as- Q = mcΔT
Given:
Mass of water = 100g
The temperature is to be raised from 10⁰C to 40⁰C
Find:
We need to determine the amount of steam to raise the temperature of water from 10⁰C to 40⁰C.
Solution:
Suppose the mass that is required by the steam is m g.
When steam condenses at 100⁰C, it releases 536 calories of heat per gram. It is then cooled to 40⁰C.
m gm of steam condensing releases 536 × m of heat.
From the specific heat formula, Q = mcΔT
Final solution temperature = m × water's specific heat × temperature drop
Final solution temperature = m × 1 × (100-40)
Final solution temperature = m × 60 = 60m
Heat released = 536 m calories of heat + 60m metres
Heat released = 596m
the amount of heat needed to raise 100 g of water's temperature to 10⁰C + m g of condensed steam from 10⁰C to 40⁰C
= (100 +m) × 1 × (40 - 10)
= (100 + m) × (30)
heat gained = Heat lost
(100 + m) × (30) = 596m
3000 + 30m = 596m
3000 = 596m -30m
3000 = 566 m
m = 5.3 gm
Thus, the amount of steam required to raise the temperature of water from 10⁰C to 40⁰ is 5.3g.
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