The temperature of 170 g of water at 50 degree celsius is lowered to 5 degree celsius by adding a certain amount of ice to it. Find the mass of ice added. Given : specific heat capacity of water = 4200 J kg-1 degree celsius and specific latent heat of ice = 336000 J kg-1.
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Explanation:
Specific heat capacity of water = 4200 kg−1 °C−1 and Specific latent heat of ice = 336000 J kg−1
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Let mass of ice added be x then we have heat lost by water = Heat used by ice. we should add 90 g of ice to water.
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