Question

The temperature of 170 g of water at 50 degree celsius is lowered to 5 degree celsius by adding a certain amount of ice to it. Find the mass of ice added. Given : specific heat capacity of water = 4200 J kg-1 degree celsius and specific latent heat of ice = 336000 J kg-1.

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Answer 1

Answer:

Answer

Let the mass of ice to be added be m

i

.

Given : S

w

=4200 J/kg

o

C L=336000 J/kg

Mass of water m

w

=170 g=0.17 kg

Change in temperature of water ΔT=50−5=45

o

C

Heat energy released by water in lowering its temperature is absorbed by ice to melt.

Using m

i

L=m

w

S

w

ΔT

∴ m

i

×336000=0.17×4200×45

⟹ m=0.0956 kg=95.6 g

Answer 2

Answer:

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