Question

The temperature of 1kg water is 80° c. if it is mixed with 40å c temperature of  water of 1kg then find out the temperature of the mixture.​

Answer 1

Answer:

mcθ  

1

​  

+mcθ  

2

​  

=mcθ  

0

​  

 

since c is constant, assuming water is heated from 0  

o

C

(1000)(20) + (800)(80)= (1800)θ  

0

​  

 

20000+64000= 84000=1800θ  

0

​  

 

θ  

0

​  

=46.67  

o

C

hence the finale temperature in θ  

0

​  

=46.67  

o

Explanation:

Answer 2

Answer:

If 1kg water = 80°c

1kg water = 40°c

then temperature of mixture

→ 1kg + 1kg = 80°c + 40°c

→ = 120°c

Hope it'll help you.