The temperature of 1kg water is 80° c. if it is mixed with 40å c temperature of water of 1kg then find out the temperature of the mixture.
Answers
Answered by
2
Answer:
mcθ
1
+mcθ
2
=mcθ
0
since c is constant, assuming water is heated from 0
o
C
(1000)(20) + (800)(80)= (1800)θ
0
20000+64000= 84000=1800θ
0
θ
0
=46.67
o
C
hence the finale temperature in θ
0
=46.67
o
Explanation:
Answered by
1
Answer:
If 1kg water = 80°c
1kg water = 40°c
then temperature of mixture
→ 1kg + 1kg = 80°c + 40°c
→ = 120°c
Hope it'll help you.
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