Question

The temperature of 546 ml of a gas at 0 C is raised until its volume becomes 600 ml, pressure remaining unchanged. Determine the new temperature of the gas.

Answer 1

Answer:

(mark brainliest pls)

PV = nRT is the ideal gas equation and it is your friend for problems like this.

Since you want V to double while keeping P and n (the number of moles) constant, it’s pretty simple.

Note that 0 C is 273 Kelvin, so rearrange:

V = rR * t0 / P, where t0 is the original temperature = 273 Kelvin

The new volume V’ = 2V at the new temperature T’

V’ = 2V = nRT’ / P

Rearrange again to get the new temperature:

T’ = V’ * P / (nR) = (2V) * P / (nR) = 2 * V * P / (nR)

But notice that V * P / (nr) is just t0, so T’ = 2 * t0, in agreement with the other answer.

Double the temperature and double the volume. Note that this assumes that the gas is behaving ideally. With real gasses, this is a close approximation.