Question

The temperature of 600g of cold water rises by 15 degree Celsius when 300 g of hot water at 50 degree Celsius is added to it. What was the initial temperature of cold water

Answer 1

Let mass or m = 600g, m1 = 300g, heat capacity of water = c. T be the initial temperature and T1 be the final temperature of the liquid.

According to the question,

 mc (T1 – T) = m1 c (50 – T1)

600 c (T1 – T) = 300 c (50-T1)


Therefore, initial temperature is equal to 5 degree Celsius.

Answer 2

please follow the above table,

we know,

m1 c1 (t1 -t) = m2 c2 (t-t2)

300 ( 50 - 30) = 600 (15 - t2) ( c1 and c2 gets ancelled)

35 = 30 - t2 ( 300÷600= 2 and 2×15=30)

therefore,

t2 = 5°C.

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