Question

the temperature of 600g of cold water rose by 15 degree celcius when 300g of hot water at 50 degree celcius was added to it. What was the initial temperature of the cold water ?

Answer 1

heat absorbed by cold body= $0.6*4200*15$
heat released by hot body= $0.3*4200*(50-\theta)$
now, heat realesed=heat absorbed, solve this to get theta. Substracting 15 from that will give you the initial temperature of the cold body.

Answer 2

tgis is ur ans:-

m = 600 gm and m' = 300 gm

c is the heat capacity of the water. 

Let T1 be the initial temp. of cold water.

T2 be the final temp. on mixing the water. 

According to the problem,



On solving we get,

T1 = 50 C.