The temperature of a gas at pressure 2 atm and volume 2 Lis 127°C Kooping its volume constant if its temperature is raised to 927°C, then its new
pressure will be
O 6 atm
o 4 atm
O2 atm
0 1 atm
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Given:
The initial temperature of the gas = 127°C= 400 K
The initial pressure of the gas = 2 atm
The initial volume of the gas = 2 L
Final temperature of the gas = 927°C= 1200K
To find:
The new pressure of the gas if volume remains constant.
Solution:
We know that:
PV=nRT
If all the terms are constants except pressure and volume then pressure is directly proportional to temperature and:
P1/T1 = P2/T2
Substituting the values we get:
2/400 = P2/1200
P2= 2×1200/400
P2 = 6 atm
Thus, the new pressure of the gas is 6 atm.
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