Question

The temperature of a gas in the closed container is 27 degree celsius if the temperature is raised to 327 degree celsius the pressure exerted isanswer fast very important question❓❓❓ from #neet​

Answer 1

Answer:

Increased by 2 times.

Explanation:

Assuming the gas to be ideal,

PV = nRT

PV = nR × (273 + 27)

P = 300 × nR/V

Let n = 1 and V = 1. That gives us

P1 = 300 × R

Let's use R = 0.0821 L-atm/mol K

That gives us P = 24.63 atm.

Now, if T = 327°C = 273 + 327 = 600K

P2 = 600 × 0.0821 = 49.26 atm

Comparing P2 and P1, we get the ratio,

P2 : P1 = 2 : 1

Therefore, pressure will increase by 2 times.

Plz mark me as brainliest..